A deck of 52 poker cards (without jokers) are divided equally into 2 piles.
If you do it for 500 times, how many times will the number of red cards in the 1st pile be equal to the number of black cards in the 2nd pile ?
do it a few times will know, however, there is a simpler way through maths (algebra)! let R1=number of red cards in deck one, so we have R1+R2=26,R1+B1=26,R2+B2=26,hence R1=26-R2 and B2=26-R2, therefore R1=B2, always the same!!
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Eton Commercial School (Tel: 6245 8494) 
do it a few times will know, however, there is a simpler way through maths (algebra)! let R1=number of red cards in deck one, so we have R1+R2=26,R1+B1=26,R2+B2=26,hence R1=26-R2 and B2=26-R2, therefore R1=B2, always the same!!
Comment by sspider May 15, 2008 @ 6:26 am